So you can now run your scala app by defining the "mainClass" property :
mvn scala:run -DmainClass=org.example.MyClass
You need to use launchers if you :
<plugin>
<groupId>maven</groupId>
<artifactId>maven-scala-plugin</artifactId>
<configuration>
<launchers>
<launcher>
<id>foo</id>
<mainClass>org.example.MyClass</mainClass>
<!-- args are optional -->
<args>
<arg>arg1</arg>
</args>
<!-- jvmArgs are optional -->
<jvmArgs>
<jvmArg>-Xmx128m</jvmArg>
<jvmArg>-Djava.library.path=...</jvmArg>
</jvmArgs>
</launcher>
<!-- you could define other launcher -->
</launchers>
</configuration>
</plugin>
Now you can run the following command to run your launcher (the classpath used is the test classpath).
mvn scala:run -Dlauncher=foo
If you don't specify launcher or mainClass then the first launcher is used, in your case, the example below is equivalent to the example above.
mvn scala:run
If you need/which to specify some additional arguments at call time use "-DaddArgs=arg1|arg2|arg3" ('|' is used as separator)
Set the property 'displayCmd' to true, to display the command line used